Air pollution is one of the biggest problems large, metropolitan areas face. Clean Currents helps to alleviate this problem. Because Clean Currents increases the efficiency (MPG) of vehicles, and boosts overall car efficiency, it reduces the amount of emissions produced by every vehicle by up to 44.4 percent. This is extremely beneficial to both the user and the environment, as it reduces smog test costs, and helps to reduce air pollution. Reduced air pollution leads to improved air quality and better health for the general community.
Proof of how Clean Currents reduces emissions by 44.4 %:
From the Journal of Materiomics, Xiao Zhang and Li-Dong Zhao states “the power generation efficiency ηp can reach 25%.” The power generation efficiency ηp relates the heat released and the electricity generated using thermoelectric materials. Using the chemical formula for the combustion of octane (gasoline), the amount of carbon-dioxide (vehicle emissions) that are reduced can be calculated:
iii) 0.18624 - 0.103610.1824= 0.443675 = 44.4% Reduction in emissions
Proof of how Clean Currents reduces emissions by 44.4 %:
From the Journal of Materiomics, Xiao Zhang and Li-Dong Zhao states “the power generation efficiency ηp can reach 25%.” The power generation efficiency ηp relates the heat released and the electricity generated using thermoelectric materials. Using the chemical formula for the combustion of octane (gasoline), the amount of carbon-dioxide (vehicle emissions) that are reduced can be calculated:
- 2 C8H18 (aq) + 25 O2 (g) --> 18 H2O (l) + 16 CO2 (g) + Heat
- Assume 1 gallon of octane (3.77541 liters)
- i) 3.78541 Liters 0.7025 g1 mL(Density of Octane) 1 mol114.23 g(Molar Mass of Octane) 162(mol ratio of Octane to Carbon-Dioxide) = 0.18624 mol of CO2 released without Clean Currents
- ii) 3.78541 Liters 0.7025 g1 mL(Density of Octane) 48 kJ1 g(Heat of Combustion) = 127.644 kilojoules of heat produced 0.555 (Fraction of Heat not Used by Clean Currents) = 71 kJ of Heat released 48 kJ1 g(Heat of Combustion) 1 mol114.23 g(molar mass) 162(mol ratio of Octane to Carbon-Dioxide) = 0.10361 mol of CO2 released with Clean Currents
iii) 0.18624 - 0.103610.1824= 0.443675 = 44.4% Reduction in emissions